19 Jul
2011
19 Jul
'11
6:44 a.m.
On 19/07/2011 3:16, John M. Dlugosz wrote:
Since the return type depends on the argument, how could I declare a result_type?
You can see how to do it here http://www.boost.org/doc/libs/1_47_0/libs/utility/utility.htm#result_of Agustín K-ballo Bergé.- http://talesofcpp.blogspot.com