18 Mar
2011
18 Mar
'11
9:53 a.m.
Search pattern: "\\u(\w{4})"
It seems that we also have to escape the "\" in "\u". The working regex seems to be:
"\\\\u(\w{4})"
I'm surprised. The first backslash was already there to escape the second. Are there maybe two steps of backslash interpretation at work, one by the C++ compiler and one by Boost.Regex? In any case, I forgot to escape the backslash in "\w", you'd probably have to give that one the same treatment. And also the ones in "\&" and "\1" in the replacement pattern.
Yes, if you want to match a literal '\' then you need to use '\\\\' in the regex - the compiler swallows one set of \'s so the regex engine then sees '\\' which is what you want... HTH, John.