From: "Ovanes Markarian"
Sorry,
I ment enable_if< is_decimal_type<T> >::type. The ::type will be expanded to
either void or a derivable type.
Maybe I'm misunderstanding, but how can I derive std::numeric_limits from enable_if, since std::numeric_limits is already defined? I can't do this:
namespace std {
template <typename T>
class numeric_limits :
private boost::enable_if::type
{
public:
static T min() { return boost::decimal::decimal_limits<T>::min(); }
};
}
and I can't do this:
namespace std {
template <typename T>
class numeric_limits<T> :
private boost::enable_if::type
{
public:
static T min() { return boost::decimal::decimal_limits<T>::min(); }
};
}
because this is not a specialization.
-
James Jones Administrative Data Mgmt.
Webmaster 375 Raritan Center Pkwy, Suite A
Data Architect Edison, NJ 08837
