Hi : Thanks for the note. fs::path( "c:\\", fs::native ) works. c:\\temp works c:\\temp\\test.xml fails ( should this fail or work? ) I'm deeper in my exploration now ... Here's a question for you. If I use a proxy class like the attached this all fails. Is there something "special" about fs::path that dictates I can't proxy it? If I compile that TuPath into a dll it fails but if it's attached to a standalone it works fine. So is there something special about fs::path? Clearly the proxy started as a "is-a" relationship and now I'm trying it as a "has-a" but to no avail. I'm getting closer .. something to do with the external linkage or rtl but the rtls are all consistent which is what's confusing me even more. Thanks; Steve a. On Apr 5, 2005 10:00 AM, John.Wismar@autozone.com <John.Wismar@autozone.com> wrote:
steve ahlgren <steveahlgren@gmail.com> wrote:
fs::path p = fs::path( "c:/", fs::native );
What happens when you use this?
fs::path p = fs::path( "c:\\", fs::native );
-------------------------------- John Wismar john.wismar@autozone.com
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