[Boost-users] shared_array const member function

26 Aug 2009

      Can any body please tell me why operator[] is defined in case of
shared_array<T> like this way:

Type & operator[](std::ptrdiff_t) const;

It reports compile time error. Consider the code:

class Widget {
            std::string classId;
public:
            std::string getClassId() const {
                        return classId;
            }
};

int main()
{
            boost::shared_array<Widget> obj(new Widget[10]);
            std::string id = obj[7].getClassId
();                               // Error
}

In my opinion operator function should be defined as follows:

const Type & operator[](std::ptrdiff_t) const;
Type & operator[](std::ptrdiff_t) ;

Please clear my consfusion. Thanks in advance.

[Boost-users] shared_array const member function

Daya S. Prasad