Hi, I would like to bind a function which takes a boost::function<void> as parameter, let's say void caller(boost::function<void (void)>& f) { f(); } void foo() {} boost::function<void (void)> foo_fun = &foo; boost::bind(caller, foo_fun)(); But what if the function has a parameter, for example void bar(int i) {} How can I create the folling a function object? boost::function<void (int)> The function object should take an int, bind it to bar and then call caller with the resulting nullary function. boost::function<void (int)> bar_fun = &bar; // doesn't work because caller and bar are being composed. boost:bind(caller, boost::bind(bar_fun, _1)) // doesn't work because caller doesn't accept a unary function. boost:bind(caller, boost::protect(boost::bind(bar_fun, _1))) Does anyone have a clean solution for that? boost::protect doesn't provide the option to evaluate the arguments (_1) but _not_ perform a composition. Regards, Christian