Alexander Shyrokov wrote:
std::for_each( a.begin(), a.end(),
boost::bind( &c::f, boost::bind( &TMap::value_type::second, _1 ), NULL ) ); Indentation does help with these things. But this still does not work I am getting:
boost_1_33_1\boost\bind.hpp(286) : error C2664: 'R boost::_mfi::mf1<R,T,A1>::operator ()<boost::_bi::result_traits<c,F>::type>(U & ,A1) const' : cannot convert parameter 2 from 'int' to 'boost::_bi::result_traits<R,F>::type & '
The problem here is that NULL is defined as 0, which is of type int. The literal 0 is implicitly convertible to any pointer type, but an int that happens to have the value 0 is not. So you need to cast the NULL to the correct pointer type first. Annoying, I know. There is a proposal for a nullptr keyword that will - hopefully - allow the above code to work as-is. In such a situation I tend to define my own nullptr: struct nullptr_t { template<class T> operator T* () const { return 0; } } nullptr; and use that instead of NULL.