Re: [Boost-users] [python] call f(shared_ptr<const A>) with shared_ptr<A>?

Malte Clasen <news@copro.org> writes:

Hi,

I usually use shared_ptrs to const as function parameters, such as boost::shared_ptr<const A>, to explicitly state that this function does not modify the pointee. Now I'm trying to do the same in boost.python:

<snip>

Is there a way to use the automatic conversion from A to const A in boost.python?

You might try: implicitly_convertible<shared_ptr<A>, shared_ptr<const A> >(); -- Dave Abrahams Boost Consulting www.boost-consulting.com