24 Nov
2004
24 Nov
'04
1:59 p.m.
Frank Birbacher
Hi!
David Abrahams wrote:
Because often the result type depends on the argument type that is actually passed:
But he is binding a pointer-to-member-variable which definately has a result type (which is the type of the member).
For the reasons that they didn't make that particular result into an adaptable unary function, you have to consult the Boost.Lambda authors. -- Dave Abrahams Boost Consulting http://www.boost-consulting.com