Re: [Boost-users] return type of boost::bind

Cheenu Srinivasan wrote:

Duane Murphy wrote:

...

The return type of boost::bind is fairly indeterminate. In order to call a bound function at a later time, look at boost::function. It does a nice job of holding on to a function that uses boost::bind.

I looked at "Using bind with Boost.Function" in the boost::function docs. Mimicing that, for my example, I tried:

boost::function bound_func = boost::bind(f, _1, 1.234); int i = 99; cout << bound_func(i) << endl;

but it throws a bad_function_call exception when bound_func(i) is invoked. How do I use boost::function for this situation?

Works for me; it's probably a compiler bug. Which compiler are you using? Try boost::function bound_func( boost::bind(f, _1, 1.234) ); instead.