Cheenu Srinivasan wrote:
Duane Murphy wrote:
The return type of boost::bind is fairly indeterminate. In order to call a bound function at a later time, look at boost::function. It does a nice job of holding on to a function that uses boost::bind.
I looked at "Using bind with Boost.Function" in the boost::function docs. Mimicing that, for my example, I tried:
boost::function<double (int)> bound_func = boost::bind(f, _1, 1.234); int i = 99; cout << bound_func(i) << endl;
but it throws a bad_function_call exception when bound_func(i) is invoked. How do I use boost::function for this situation?
Works for me; it's probably a compiler bug. Which compiler are you using? Try boost::function<double (int)> bound_func( boost::bind(f, _1, 1.234) ); instead.