Re: [Boost-users] [iterator] Writable transform_iterator: how to?

In article , "Patrick Loney" wrote:

struct f : public std::unary_function { int operator()(int& x) { return x; } };

No, nor does struct f : public std::unary_function { int operator()(int x) { return x; } }; or struct f { typedef int& result_type; result_type operator()(int& x) { return x; } }; The compiler complains upon dereferencing. But my goal is to be able to modify the iterator's value (i.e., to write *it = value), so the return type of the function object must be a reference. Maybe, I can use iterator_adaptor instead of transform_iterator? I have forgotten to mention that I am using Boost 1.34.1. Nicola