struct employee {
std::string name;
};
typedef multi_index_container<
employee,
indexed_by<
hashed_unique >
mi;
If I want to change the index to make it case-insensitive I have to write
my own key extractor, right? Would the following code then be correct (it
is based on boost::multi_index::member)?
template
struct caseinsensitive_string
{
typedef std::string result_type;
template<typename ChainedPtr>
std::string operator()(const ChainedPtr& x) const
{
return operator()(*x);
}
std::string operator()(const Class& x) const
{
return boost::algorithm::to_lower_copy(x.*PtrToMember);
}
std::string operator()(Class& x) const
{
return boost::algorithm::to_lower_copy(x.*PtrToMember);
}
std::string operator()(const boost::reference_wrapper<const Class>& x)
const
{
return operator()(x.get());
}
std::string operator()(const boost::reference_wrapper<Class> x) const
{
return operator()(x.get());
}
};
With the following typedef I get a container which does not change the
name of an employee (I want to retain the name without making it lower- or
uppercase) but refuses items with the same case-insensitive name?
typedef multi_index_container<
employee,
indexed_by<
hashed_unique >
mi2;
Boris
