Re: [Boost-users] boost::serialization - extra 6 bytes overhead question?

ok I have this working, however... packet_base: 12 packet_ping: 44 0 1 0 0 0 1001 44 2 3 7 32 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ^ packet actually starts here(packet_length). There are 6 extra bytes overhead I know that 1001 is my class version. What are 0, 1, 0, 0 and 0? I need this info for writing packet de-serialization in other languages. Thanks in advance. On Apr 14, 2008, at 8:21 AM, j.c. wrote:

Sweet, just what I was looking for, thanks.

On Apr 14, 2008, at 8:31 AM, Robert Ramey wrote:

...

lookup base_object in the documentation.

Robert Ramey

"j.c." wrote in message news:CB290CFC-9ABD-4FF9-80C1-766E3063F8A6@mac.com ... I am writing a packet base class that can be serialized. The class so far looks like:

class packet_base { using namespace boost;

public: packet_base(); ~packet_base();

friend class boost::serialization::access; template <typename Archive> void serialize(Archive & ar, const unsigned int version) { ar & m_length; ar & m_type; ar & m_method; }

private:

uint16_t m_length; uint16_t m_type; uint16_t m_method; };

The question now is how can I derive class A from packet_base and have both packet_base and A's variables serialized? Obviously base_class needs to be archived first so it's variables are at the front of the buffer.

Thanks in advance. J

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