Re: [Boost-users] [regex] matchinf info with merged regex

13 Jul 2006

      John Maddock wrote:
...
The way to find out which sub-expression matched is simply:
match_results<something> what;
...
for(unsigned i = 1; i < what.size(); ++i)
{
  if(what[i].matched)
    std:cout << "sub-expression " << i << " matched " << what[i] << 
std::endl;
}
First, thanks for the reply, it's nearly what I need ;)

Actually, either I misunderstood something or is this code giving me
just the first part in the regex that matches ?

e.g. if I try

<code>

std::string myString ="jayjay";
std::string myRegexSearch = "(ay)|(j)(?=[aeiouy])";

boost:regex* myRegexp = new boost::regex (myRegexSearch,
boost::regex::normal);

boost::cmatch what;

boost::regex_search (myString , what, *myRegexp);

for(unsigned _ = 1; _ < what.size(); ++_)
{
   if(what[_].matched)
      printf("rule [%d] matched '%s'\n",_,what[_]);
}
delete myRegexp;

</code>

The output is

rule [2] matched 'jayjay'

where I expected it to tell me "rule 1" and "rule 2" matched!

Am I missing something?

Thanks again,

Line.

Re: [Boost-users] [regex] matchinf info with merged regex

Line Oddskool