I haven't been following this thread closely, but I know enough math to say that lim_{x->0} (0/x) is 0. When evaluating a limit, one does not simply substitute the limiting value into the expression. The limit is the value of the expression as the variable gets arbitrarily close but not equal to the limiting value. As x gets arbitrarily close to 0, 0/x remains exactly 0. I have no clue, how this impacts the original issue.
Cheers.
Curtis Gehman Burlingame, CA
Another way of looking at it is to use L'Hopital's rule: lim_{x->0} ((x-x)/min(|x|,|x|)) => lim_{x->0} ((x-x)/x) => d/dx(x-x) / d/dx(x) => (1-1) / 1 => 0 Like Curtis says, no idea exactly what that means for the original question. Jerry