Looks like you need something like a barrier:
http://www.boost.org/doc/libs/1_47_0/doc/html/thread/synchronization.html#th...
2011/9/11 Kraus Philipp
Am 11.09.2011 um 22:14 schrieb Igor R:
I create a thread group and run the group with join_all(). My code shows like: for(i=0; i < runs; ++i) { threadgoup.join_all(); do something with the results } So I run the thread group n times. Is this the correct way or can I call join_all only once on the group?
You do not "run the group with join_all". join_all() waits (blocks) until the execution of all the threads in the group is complete - that's all.
That's correct, because the calls after the join_all need the results of all threads. The algorithm, that I use, has some parallel and serial parts, so I would run the parallel party with a thread group, wait until the group has finished and run the serial part.
This is well documented: http://www.boost.org/doc/libs/1_47_0/doc/html/thread/thread_management.html#...
I have read the documentation, but there is only the postcondition explained "Every thread in the group has terminated". The algorithm is a iteration algorithm, so I have create code like this:
creating thread group for(i=0; i < iterations; ++i) { run threadgroup for parallel part, till all threads finished run serial part }
So I would like to ask for, if the thread group is created, and I call the join_all within the loop, each "join_all" starts the full group again on each iteration or need I create a new threadgroup on each iteration (join_all can be called only once on a group)?
Thanks
Phil
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