Hello All ! Please tell, can I create nullary functor returning predefined value, using boost::function & boost::bind ? Example uses "portable" syntax of boost::function : #include <boost/bind.hpp> #include <boost/function.hpp> struct InterfaceA; InterfaceA *getInterface (); template<typename T> T forward ( T t ) { return t; } int main ( int, char ** ) { typedef boost::function0<InterfaceA *,void> functor_type; // Value of InterfaceA * supplied by getInterface () function. Usage is straightforward : functor_type f1 = boost::bind ( getInterface ); InterfaceA *p = NULL; // Value of InterfaceA * is known here. How to create functor, returning it ? // functor_type f2 = boost::bind ( ??? ); // Possible workaround. Can I do this without forward<> template function ? functor_type f3 = boost::bind ( &forward<InterfaceA *>, p ); return 0; } Thanks! Yuri.