Re: [Boost-users] boost::any Question

typeid() gives you a reference to a type_info object. Here you could ask for the typename name() and using a map you could use a switch statement. This is very slow since the string lookup, but it works. Another solution would be a thin wrapper class around all of your types that has a static int member and pointer to the real object. Here, you simply use the static and in the switch statement. I don't know if there is more boost-like way available? Perhaps someone else will have a higher performance and cleaner solution. Christian On 10/10/05, Piyush Kapadia wrote:

True that I just need limited type supported and not entire universe of types, I have also seen following, but it would mean to put it in series of if(is_int), elseif(is_char_ptr) kind of statements, switch statement would be more cleaner, that why I thought type_traits may offer cleaner solution.

Performance is also criteria.

On 10/10/05, Christian Henning wrote:

...

I took a look at the examples in the Boost::Any documentation and found

this:

...

bool is_int(const boost::any & operand) { return operand.type() == typeid(int); }

bool is_char_ptr(const boost::any & operand) { try { any_cast(operand); return true; } catch(const boost::bad_any_cast &) { return false; } }

bool is_string(const boost::any & operand) { return any_caststd::string(&operand); }

Is that what you're looking for?

Christian

_______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users

_______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users