Re: [Boost-users] shared_ptr with template class

Jonathan Biggar wrote:

You can drop a definition of the shared pointer inside the template class:

template<typename T> class Foo { public:

typedef shared_ptr<Foo> Ptr;

};

and then you could refer to it as Foo<T>::Ptr, although you'd need to use "typename" in some circumstances.

And of course that won't work if you need to use the shared_ptr in contexts where Foo is not defined yet. -- Jonathan Biggar jon@levanta.com