Surya Kiran Gullapalli wrote:
Hello all, The following question may not be related to boost, but if a solution can be found with boost or otherwise would be great.
I've a base class with a function template.
I derive from base class and try to have a specialization for the function template in derived class
I did something like this.
////////////////////////// Header file begin ////////////////////////// class Base { .. template <typename T> fun (T arg) { ... }
};
class Derived : public Base { ... } ;
template <> Derived::fun(int arg);
///////////////////////// Header file end ////////////////////////////
and in .cpp file I've provided implementation for the template specialization.
This works fine with MSVC 8.0 and g++ complains about lack of function declaration fun in Derived class.
I do not know which compiler is behaving correctly. Any help in this is greatly appreciated.
You can't do this. I don't think that it even does what you want with msvc. (Base().fun(1) will call the specialization) In general function templates should be overloaded rather than specialized. class Base { template<typename T> void fun(T arg); }; class Derived : public Base { using Base::fun; void fun(int); }; In Christ, Steven Watanabe