Re: [Boost-users] boost::lambda to replace a for loop

On Mon, Jul 28, 2008 at 7:01 PM, Steven Watanabe wrote:

AMDG

Marshall Clow wrote:

...

At 12:00 AM -0500 7/27/08, Meryl Silverburgh wrote:

...

for (vector::const_iterator iter = aList.begin() ; iter != aList.end(); ++iter) {

A* anA = (*iter);

// break out the for loop if aMethod return true; if (anA->aMethod()){ break; }

Isn't this what std::find_if does?

std::find_if is not quite equivalent to the for loop, because std::find_if is not allowed to modify the input sequence.

Ok, here's myquestion: What does exactly mean that std::find_if is not allowed to change the sequence? How does the code. It is not changing the vector in any way (just using a constant iterator) it is not even modifying the contents of the vector. It is just calling a (possibly not constant) method through a (constant) pointer. To me that is not modifying the input sequence. Or is it more a general concern that they are not equivalent even if in this case std::find_if could be used? David