Re: [Boost-users] How to expose self defined type in boost.python

14 Jan 2008

      I checked the maillist history, and there are guys who have the same
question with me.

class btQuadWord
{
        protected:
                btScalar m_x;
                btScalar m_y;
                btScalar m_z;
                btScalar m_unusedW;

        public:
                SIMD_FORCE_INLINE const btScalar& getX() const { return m_x;
}
};

 class_<btQuadWord>("btQuadWord")
        .def("getX", &btQuadWord::getX)
        ;
see here: http://lists.boost.org/boost-users/2007/05/27828.php

the same question is, when the function return a value which type is not a
basic type ( even a pointer ), there will be errors.

On 1/14/08, Huang You Gong <huangyougong@gmail.com> wrote:
...
Hi,
I try to use boost.python to invoke C++ library in Python, so I need to
expose types and classes.
Here is the c++ head file:
*typedef int XTYPE;*
*class XCLASS*
*{*
*public:*
*        XTYPE getvalue( void ){ return XTYPE( 3 ); }*
*};*
So I write exposing code in BOOST_PYTHON_MODULE like this:
*BOOST_PYTHON_MODULE( x )*
*{*
*        class_< XCLASS >( "XCLASS" )*
*                .def( "getvalue", &XCLASS::getvalue, return_value_policy<
copy_non_const_reference >() )*
*        ;*
*}*
but there is compiling error as using of undefined type.
what shall I do to make the type XTYPE known by boost.python?
Thanks in advance!
--
Huang You Gong
-- 
Huang You Gong