Hello, I'm a bit confused about the source code snippet at http://www.boost.org/doc/libs/1_36_0/libs/gil/doc/html/gildesignguide.html#I... and especially, since I can't find any way to get that snippet compiled: step3=color_converted_view<rgb8_view_t,gray8_pixel_t>(step2); 1.) What's the proper return type of color_converted_view in this example? 2.) Is the snippet above correct at all?, the template is defined as: 00181 template <typename DstP, typename View> 00182 inline typename color_converted_view_type<View,DstP>::type 00183 color_converted_view(const View& src) { 00184 return color_converted_view<DstP>(src,default_color_converter()); 00185 } in http://www.boost.org/doc/libs/1_36_0/libs/gil/doc/html/g_i_l_0221.html So shouldn't it be color_converted_view<gray8_pixel_t,rgb8_view_t>?, with pixel type first and view type second Which leads me to the next question why is the type order swapped for the return value type definition? The following snippet: rgb8_image_t img; jpeg_read_image("bild.jpg", img); jpeg_write_view("bild_transform.jpg", color_converted_view<gray8_pixel_t,rgb8_view_t>(view(img))); atleast outputs a properly grayscaled image, the original line from the example obviously throws an error during compilation, but I still like to know what the proper return type of color_converted_view is. Thanks for any help, Stefan