[Boost-users] [BGL] - deriving from filtered_graph

When using a type that I derived from filtered_graph, if I use operator[] on the instance, e.g. derived_from_filtered_graph_instance[descriptor].foo = bar; I get the following error: C:\dev\vendor\boost\1.37.0\boost/graph/graph_traits.hpp(124) : error C2039: 'edge_bundled' : is not a member of 'btra::restricted_graph<Graph>' 1> with 1> [ 1> Graph=btra::undirected_graph 1> ] 1> C:\dev\vendor\boost\1.37.0\boost/graph/graph_traits.hpp(137) : see reference to class template instantiation 'boost::edge_bundle_type<G>' being compiled 1> with 1> [ 1> G=btra::restricted_graphbtra::undirected_graph 1> ] 1> C:\dev\btra\trunk\btra/two_way/esri_io.h(186) : see reference to class template instantiation 'boost::graph::detail::bundled_result' being compiled 1> with 1> [ 1> Graph=btra::restricted_graphbtra::undirected_graph, 1> Descriptor=boost::detail::edge_desc_impl 1> ] and if I typedef edge_bundled in the derived class, everything seems to work okay. filtered_graph doesn't contain the typedef, the Graph type does, so does this mean that to be more correct I should specialize graph_traits for my derived type, or is just having the typedef enough? Also, in the filtered_graph documentation, it says it models VertexAndEdgeListGraph and PropertyGraph, but neither of those concepts mention edge_bundled as an associated type. Thanks in advance, --Michael Fawcett