Hi Andrey, you can pass list by value. Compiler should be smart enough to eliminate the temporary. On the other hand, if you vector is always constant consider using a fusion vector. You can also introduce a helper function, which fills the vector with the desired list and returns it: struct sss { sss() : v(vector_items) {} private: // this function should be inlined with temporary elimination static vector<int> vector_items() { vector<int> v = list_of...; return v; } }; Hope that helps, Ovanes On Wed, Mar 17, 2010 at 8:30 PM, Andrey Torba <andreytorba@gmail.com> wrote:
On 17 March 2010 17:58, Ovanes Markarian <om_boost@keywallet.com> wrote:
vector<int> v(my_iterator(list_of(1)(2)), my_iterator());
I think that result of `list_of` will be destroyed after `my_iterator(...)` call, so `my_iterator` will not be valid.
-- Regards, Andrey _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users