Hi Emil,
I was able to figure out some more information about the issue and I could
isolate it a little bit more. First it doesn't matter if it is a static or
a shared library. Second it is not directly related to the
*Boost.Exception*library but to the template class
*error_info* which is used to create the predefined errinfo_xyz types. It
is enough to instantiate the *errinfo_api_function* type in both
doSomething() methods in the both implementation files. I am not so good in
templates but I guess that the compiler creates the same symbol in both
object files (ClassA.o and ClassB.o) for the type *errinfo_api_function.* I
can see this via nm that I have the following line in both object files:
*ClassA.o*
*0000000000059860 s __ZTIN5boost21errinfo_api_function_E*
*
*
*ClassB.o*
*0000000000059870 s __ZTIN5boost21errinfo_api_function_E *
*
*
Now, when the linker tries to link ClassA.o and ClassB.o to the main.o the
both symbols clashes. But that would mean I could never use *Boost.Exception
* or any other template instantiated type in a library.
Best Regards
Georg
2013/10/2 Emil Dotchevski
On Tue, Oct 1, 2013 at 2:16 AM, Georg Leidinger < georg.leidinger@googlemail.com> wrote:
Dear readers,
I encountered a problem in my project when using *Boost.Exception* with the predefined types errinfo_xyz in a library project. I have two classes ClassA and ClassB in my library which both throw a boost::exception with errinfo_api_function type in their implementation file (.cpp) These both classes are compiled into a static library with the C/C++-Flags -fvisibility=hidden. Then I have a main.cpp which creates an instance of ClassA and ClassB and links to the library which contains ClassA.o and ClassB.o. When I compile the main.cpp I get the linker error duplicate symbol for the errinfo_api_function object in ClassA.o and ClassB.o. If I remove the visibility=hidden flag, it links without problems. I am not an expert on the compiler flags, but I saw that many libraries use the visibility=hidden flag so I think it would be good, if my lib could also use it.
Honestly I have no idea why this would happen. Anyone?
-- Emil Dotchevski Reverge Studios, Inc. http://www.revergestudios.com/reblog/index.php?n=ReCode
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