Does the initialization form I showed earlier, e.g.
std::vector newvec= list_of().range(RecVec.begin(),db).range(newdata).range(de,RecVec.end());
know to get the total length first, or will it keep re-allocating storage with each underlying insertion? That is, do I get a performance benifit from manually doing:
std::vector newvec;
newvec.reserve (... add up the sizes of my three ranges ...)
newvec += range(RecVec.begin(),db).range(newdata).range(de,RecVec.end());
Hmm, I'm sure the last line would be somewhat different.
Anyway, do I need to reserve first, or will it be reasonably smart about that?
--John
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