"Andreas Sæbjørnsen" <andreas.saebjoernsen@gmail.com> wrote in message news:954f1fae0601131820sfd56f77pb31a9d114f8a343e@mail.gmail.com...Hi,
I am currently experimenting with writing a compiler tool which generates the code necessary for using boost::serialization. While working on this I found that I am unable to serialize a variable declaration which is a reference to a class constructed with the default constructor '()'( ex. class foo var(); ). I have tried to find an explanation for this in the examples, documentation and through searching the web without success. Using pointers it works fine with the
default constructor and I do not see why it should be any different for references (as references in essence are pointers). Is it possible to serialize a class constructed using the default constructor using boost::serialization, and if so how?
Example:
#include <fstream>
// include headers that implement a archive in simple text format
#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_iarchive.hpp>
class gps_set
{
friend class boost::serialization::access;
public:
int x;
gps_set::gps_set(){ x = 2;};
virtual gps_set::~gps_set(){};
gps_set::gps_set(int i) : x(1) {};
private:
template<typename Archive>
void serialize(Archive& ar, const unsigned int version){
ar& x;
}// End method: X::serialization
};
int main()
{
// save the schedule
std::ofstream ofs("filename");
// create class instance
//Compile time error if s1() is used. No error if s1(1) is used.
const gps_set s1();
// save data to archive
{
boost::archive::text_oarchive oa(ofs);
// write class instance to archive
oa << s1;
// archive and stream closed when destructors are called
}
};
Thanks,
Andreas Saebjoernsen
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