[Boost-users] enable_if question

Hi, I understand that by using enable_if the following way: template <class T> T foo(T t, typename enable_if<boost::is_arithmetic<T> >::type* dummy = 0); I can include/exclude the appropriate function overloads. When I write: template<class T> T foo(T t, typename enable_if<[condition1]>::type* dummy = 0, typename enable_if<[condition2]>::type* dummy = 0); Does this mean an AND-relationship between condition1 and condition2? (So that a particular overload is enabled if and only if both conditions evaluate to true?) Thx, Gus