Re: [Boost-users] fusion::result_of::transform<Seq1,Seq2,F>

13 Sep 2008

      Steven Watanabe wrote:
...
AMDG
e r wrote:
...
// probably not what result_of::transform expects, based on compile
// errors (below)
  template
  struct result{
     typedef typename Metafun::type type;
  };
Fusion uses Boost.ResultOf.
http://www.boost.org/doc/libs/1_36_0/libs/utility/utility.htm#result_of
In Christ,
Steven Watanabe
Thanks. I read the link above before posting as well as the proposal:

//example from proposal.
struct square_ {
  template<typename T> struct result {
    typedef T type;
  }

  template<typename T> T operator()(T& x) const
  {
    return x*x;
  }
};

but I'm not qualified enough to deduce the right answer in my case. i
thought id would be like this:

template<typename Arg1>
struct fun{
  template
  struct result{
     typedef typename Metafun::type type;
  };

  template
  typename Metafun::type
  operator()(const Metafun& meta,const Arg2& arg2)const{
      typedef typename Metafun::type result_type;
      return result_type(args,arg2);
  }
};

but apparently it's not correct. I guess I can't fully make sense of
F::result::type. any hint here would be really helpful.

thanks!