Re: [Boost-users] Why fusion::map<> types not the same?

2013/9/3 niXman

Hi,

Why 'type' is not same as 'expected' in the example below?

Because 'push_back' returns you a 'view'.

using origin = boost::fusion::map< boost::fusion::pair

...

; using expected = boost::fusion::map< boost::fusion::pair ,boost::fusion::pair ;

using type = boost::fusion::result_of::push_back< origin ,boost::fusion::pair

...

::type;

static_assert(std::is_same::value, "error!");

The second question is, how can I get the same type as 'expected' when using 'result_of::push_back<>::type' ?

Try 'as_map' HTH