Re: [Boost-users] How can I save the values in lambda expression? Can any one with kindness help me?

9 Jul 2009


      AMDG

fmingu wrote:
...
I am using Dev-C++ with boost lambda expression, I wrote:
....................
int nnumber;
int switchvalue;
typedef std::map IIPrimemap;
IIPrimemap primemapvec;
 # define BetaKGre2   1
 # define EqualToOne  2
 #define  ProductOfKPrime  3
.....................
  if_then_else(var(nnumber)==1,var(switchvalue)=EqualToOne,
  if_then_else(constant(count_if(primemapvec.begin(),primemapvec.end(),
       bind(&IIPrimemap::value_type::second,_1)>2)>0),
        var(switchvalue)=BetaKGre2,var(switchvalue)=ProductOfKPrime));
  std::cout<<" the var(switchvalue) is  "<
without any expression of var(switchvalue).
I do not know how to save the values in lambda expression and where is wrong? 
Can I use *var(switchvalue) instead of var(switchvalue)?
Can anyone with kindness help me?
Think about it. What exactly is var(switchvalue)?
What does std::cout << var(switchvalue) do?

In Christ,
Steven Watanabe