Hi guys,
I'm very new to boost.python, so my question might have been already answered.
I'm having a lot of trouble creating interfaces for class member
functions that return a reference to an object.
For example if we have the following class:
class btQuadWord
{
protected:
btScalar m_x;
btScalar m_y;
btScalar m_z;
btScalar m_unusedW;
public:
SIMD_FORCE_INLINE const btScalar& getX() const { return m_x; }
};
and we have the following interface code:
class_<btQuadWord>("btQuadWord")
.def("getX", &btQuadWord::getX)
;
I would get the following error messages (ignore the line numbers):
/usr/include/boost/python/detail/invoke.hpp: In function 'PyObject*
boost::python::detail::invoke(boost::python::detail::invoke_tag_, const RC&, F&, TC&) [with RC =
boost::python::detail::specify_a_return_value_policy_to_wrap_functions_returning, F = const btScalar& (btQuadWord::*)()const, TC =
boost::python::arg_from_python]':
/usr/include/boost/python/detail/caller.hpp:199: instantiated from
'PyObject* boost::python::detail::caller_arity<1u>::impl::operator()(PyObject*, PyObject*) [with F = const btScalar&
(btQuadWord::*)()const, Policies =
boost::python::default_call_policies, Sig = boost::mpl::vector2]'
/usr/include/boost/python/object/py_function.hpp:38: instantiated
from 'PyObject*
boost::python::objects::caller_py_function_impl<Caller>::operator()(PyObject*,
PyObject*) [with Caller = boost::python::detail::caller >]'
interface.cpp:112: instantiated from here
/usr/include/boost/python/detail/invoke.hpp:88: error: no match for
call to '(const
boost::python::detail::specify_a_return_value_policy_to_wrap_functions_returning) (const float&)'
Now, btScalar here is just a #define for double, I've had similar
problems when the return reference is to a class object.
Is there anyway to get around this problem?
Thanks a lot.
Patrick
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