Fabio Fracassi wrote:
Hello,
I am trying to use the operators.hpp templates to create the following behaviour.
I have a templated class like this.
template <class T> class example {}
now I want to do something like this:
example<SomeType> r; example<SomeType> a; example<AnotherType> b;
r = a * b
To write the multiplication manually I would have to write a function template
template <class T, class OtherT> example<T> operator*(const example<T>& op1, const example<OtherT>& op2);
So, now my question is: How can this be done with operators.hpp? Obviously ...
template <class T> class example : boost::multiplicative2<example<T>, example<OtherT> > {
template <OtherT> example<T>& operator*=(const example<OtherT>& op); template <OtherT> example<T>& operator/=(const example<OtherT>& op); }
.... won't work, since "OtherT" isn't defined at its first occurrence. Is there a way to do what I intended, or do I have to write these operators manually?
You have to write them manually. Of course you could write your own multiplicative2 that defines templated friend functions, but it hardly seems worth the trouble. -- Dave Abrahams Boost Consulting http://www.boost-consulting.com