Re: [Boost-users] [MPL] no invoke<T>?

2011/4/1 Noah Roberts

How do you intend to use invoke? template < typename Sq > // Sq is full of metafunctions struct do { typedef typename fold < Sq , start_state , funky,_1>

...

::type };

I would like to empasize here, that I'm no expert -- on the contrary, I'm trying to learn bases of mpl ;-) I don't understand your example above. I think 'do' cannot be a name of a struct, and typedef typename fold<...>::type seems to be missing something... Did you mean: struct do_ { typedef typename fold < Sq , start_state , funky,_1>

::type type; };

Could you please explain, what funky does, and start_state too? I would like to see an example I can compile, and if my understanding is correct, make a simple modification to avoid the need for invoke. Regards, Kris