Hi Ion,
I'm on 64-bit Linux (SuSe 10.0) using the Intel compiler 9.0 or gcc 4.0.2.
Here is some rough code that may better explain what I'm trying to do:
int Fun1( bufferIndex, expectedProgressState, newProgressState, timeoutTime)
{
boost::shmem::shared_timed_mutex::scoped_timed_lock lock( mutex,
timeoutTime)
if (lock.locked() == true)
{
while ( mp_bufferIndex[bufferIndex].m_progressState
!= expectedProgressState)
{
if (
mp_bufferIndex[bufferIndex].m_bufferCondition.timed_wait( lock, timeoutTime)
== false)
{
// Timed out on condition
return timedOut;
}
}
// Change the progress state
{
else
{
// mutex timed out
return timedOut;
}
return success;
}
I hope this makes sense. In this test, the value of the
expectedProgressState is never true, in order to force the timeout.
Basically I obtain the mutex before we even wait on the condition variable.
Let me know if I've gone wrong with the pattern I'm using.
Cheers,
Steve.
On 24/05/06, Ion Gaztañaga
Hi Steve,
Can you give me some more information about this? Platform, OS, compiler... If you could do a small test case it would be even better.
Regards,
Ion
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