Re: [Boost-users] [boost-users][lambda] calling a functor in-place

typedef boost::function functor; std::vector<functor> functors; ... using namespace boost::lambda; std::for_each( functors.begin(), functors.end(), bind(&functor::operator(),_1));

Oh, I see... So the explicit bind is unavoidable :(. Is there any reason for this? After all, lambda allows compact expressions like _1 = 1 , so why wouldn't it allow _1() ?