21 Jul
2014
21 Jul
'14
9:59 a.m.
On 7/20/14, 12:55pm, Joaquin M Lopez Munoz wrote:
This is off-topic, but you don't need to specialize std::less for __uint128_t because the default implementation does exactly the same as your specialization (both use operator<). [...]
Thanks Joaquin, and sorry for the OT. I thought it was a problem regarding std::less. Thanks again!