On Sun, Nov 6, 2011 at 8:52 PM, Robert Jones
The shared_ptr docs suggest that a smart pointer employing a null deleter can be implemented using a functor. Why prefer a functor to a function?
Thanks Gents - The phrasing of my question was hopelessly lax: I appreciate in the general case why one might choose to use a functor rather than a function as a callable object, what I didn't grasp (and there may be nothing to grasp), was why this (from the shared_ptr docs) struct null_deleter { void operator()(void const *) const { } }; Is implemented as a functor rather than a function. It's already void*, so I think no considerations of static polymorphism or templating, and no state, but maybe there's something else I've not thought of? Thx - Rob.