Re: [Boost-users] boost::lexical_cast: where to declare operator<<

AMDG On 09/07/2011 02:03 AM, Nagaev Boris wrote:

I'm implementing boost::lexical_cast for class A. When operator<< is declared in the same namespace, as class A, it works:

<snip>

But if operator<< is declared in root namespace, it will not compile:

That's how name lookup works in templates. operator<< has to be in a namespace associated with A. In Christ, Steven Watanabe