Hi, I would like to know how can I create a 10 bits view that makes it possible to use interleaved_view. My data are described as follow: R10G10B10A10;R10G10B10A10;R10G10B10A10;R10G10B10A10;..... You understand easily that a rgba pixel is stored on 40 bits... I tried this: typedef bit_aligned_pixel_reference<uint64_t,
mpl::vector4_c<uint16_t, 10, 10, 10, 10>, rgba_layout_t, true> rgba10101010_ref_t; // A mutable iterator over RGB101010 pixels typedef bit_aligned_pixel_iterator<rgba10101010_ref_t> rgba10101010_ptr_t; typedef std::iterator_traits<rgba10101010_ptr_t>::value_type rgba10101010_pixel_t; // View type from pixel type typedef view_type_from_pixel<rgba10101010_pixel_t>::type rgba10101010_view_t;
rgba10101010_view_t src;
But it does a mess with my pixels... (and makes it impossible to use copy_and_convert_pixels(src, rgba16_view_t(view(img))); ) If anyone could help me, that would be great ! Thank you by advance, Eloi.