Re: [Boost-users] functors with function_traits

Steven Watanabe wrote:

AMDG

Christoph wrote:

...

Do function_traits work with functors?

<snip>

Err, what do you want to happen for an overloaded or templated function object? Indeed, I was thinking of the simple case of non-overloaded, non-templated functors.

typedef BOOST_TYPEOF(FUNCTION::operator()) mf_type;

Then mf_type will be (e.g.) int (XYZ::*)(int) const, which can be broken down by the Function Types library. I'll look into that. Maybe I can create a Boost.Function from the functor and use some of Boost.Function's typedefs?

Thank you.