Re: [Boost-Users] Why "explicit" in shared_ptr's constructor?

You could shorten things with this (untested) function:

template <typename T> boost::shared_ptr<T> make_sp(T* p) { return boost::shared_ptr<T>(p); }

Which, IMHO, should be added to the boost shared pointer library (as make_shared_ptr) along with a version which takes auto_ptr<T> (which shared_ptr also has an explicit constructor for). George Heintzelman georgeh@aya.yale.edu