Hello,
I've encountered a problem compiling code that uses boost
multi_index_container. I'm using both Microsoft Visual Studio 2005 and
Apple's gcc 4.0.1. Visual Studio was very picky about how I used
namespaces. I finally got it working with the code below.
The key to success was the 'using namespace boost::multi_index' line. If
I attempted to prefix the members directly, eg.
typedef typename boost::multi_index::nth_index_const_iterator<0>::type
left_const_iterator;
or
namespace mi=boost::multi_index;
typedef typename mi::nth_index_const_iterator<0>::type left_const_iterator;
it would fail to compile.
However, when I attempt to compile the same code on Mac OS X using gcc
4.0.1 I get the following errors. Does anyone know why?
src.cpp:98:error: wrong number of template arguments (1, should be 2)
/boost/boost/multi_index_container_fwd.hpp:46: error: provided for
'template struct
boost::multi_index::nth_index_const_iterator'
src.cpp:98: error: expected ';' before 'left_const_iterator'
src.cpp:99: error: wrong number of template arguments (1, should be 2)
/boost/boost/multi_index_container_fwd.hpp:46: error: provided for
'template struct
boost::multi_index::nth_index_const_iterator'
src.cpp:99: error: expected ';' before 'right_const_iterator'
-----code----
using namespace boost::multi_index;
88 template
89 class SimpleBiMap : public multi_index_container<
90 pair,
91 indexed_by<
92 ordered_unique, A,
&pair::first> >,
93 ordered_unique, B,
&pair::second> >
94 > >
95 {
96 public:
97 typedef pair mytype;
98 typedef typename nth_index_const_iterator<0>::type
left_const_iterator;
99 typedef typename nth_index_const_iterator<1>::type
right_const_iterator;
100
101 SimpleBiMap(const mytype init[], int N) {
102 for (int i=0; i().find(key); }
108 right_const_iterator find(const B &key) const { return
get<1>().find(key); }
109
110 left_const_iterator left_end() const { return
get<0>().end(); }
111 right_const_iterator right_end() const { return
get<1>().end(); }
112
113 const B &operator[](const A &key) const { return
get<0>().find(key)->second; }
114 const A &operator[](const B &key) const { return
get<1>().find(key)->first; }
115 };
---code---
Thank you,
Dwight Kelly
Apago, Inc.
