Re: [Boost-users] [function] template deduction issues

AMDG Robert Dailey wrote:

If you only need to deal with function pointers,

template<class T> void Subscribe(void (*callback)(const packet_t&)) { Subscribe(boost::function(callback)); }

What about for function objects?

There is no way to deduce what a function object can be called with since it can have an overloaded operator(). To deal with monomorphic unary function objects that follow the std library conventions, use this: (warning untested.) BOOST_MPL_HAS_XXX_TRAIT_DEF(argument_type); template<class T> typename boost::enable_if::type Subscribe(const T& t) { Subscribe(boost::function::type&)>(callback)); } In Christ, Steven Watanabe