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view of multiarray without knowledge of dimension
by graphicsMan69 (sent by Nabble.com) 03 Feb '06

03 Feb '06

Hi all - My basic need is to step through a portion of my multiarray at runtime. I don't know the dimension apriori, since the class I'm writing is templatized on dimension. This means that the multiarray can serve my other purposes just fine, since the dimesion is compile time constant, but I don't know the number of [] and the nesting of loops I'll need to iterate through the valid indices in my range min to max in my multiarray. Essentially, if I could specify a view of my multiarray, likely it shouldn't be too hard to iterate through the elements of that sub-multiarray, even without knowing the dimension at coding time. Anyone know of a way to get a view without knowing the dimensions at coding time? Thanks, Brian -- View this message in context: http://www.nabble.com/view-of-multiarray-without-knowledge-of-dimension-t10… Sent from the Boost - Users forum at Nabble.com.

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Re: [Boost-users] Getting started with Boost: what did you need toknow?
by Nat Goodspeed 03 Feb '06

03 Feb '06

> -----Original Message----- > From: boost-users-bounces(a)lists.boost.org [mailto:boost-users- > bounces(a)lists.boost.org] On Behalf Of Drumheller, Michael > Sent: Friday, February 03, 2006 12:51 PM > To: boost-users(a)lists.boost.org > Subject: Re: [Boost-users] Getting started with Boost: what did you need > toknow? > > Main stumbling point for me was bjam. > I have to say, I'm almost embarrassed to be writing this, because it > seems like nobody on this list ever complains about bjam. So maybe it's > just me. But to me, bjam is an incomprehensible monster, [Nat] It's not just you. The more we looked at bjam, the less convinced we were that we even wanted to become good at it. When it didn't work for us right out of the box (building with MSVC 7.1 + STLport), and initial futzing showed little promise, we just constructed our own MSVC projects for the Boost libraries we needed to build, and have never looked back.

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Re: [Boost-users] Bind/lambda arithmetic question
by Nat Goodspeed 03 Feb '06

03 Feb '06

> -----Original Message----- > From: boost-users-bounces(a)lists.boost.org [mailto:boost-users- > bounces(a)lists.boost.org] On Behalf Of Stephen Gross > Sent: Friday, February 03, 2006 12:52 PM > To: Boost > Subject: [Boost-users] Bind/lambda arithmetic question > > ============================= > struct Foo > { > double getX() const{ return 5; } > double getY() const { return 10; } > }; > > Foo f; > > double z = (boost::bind(&Foo::getX, boost::ref(f)) / > boost::bind(&Foo::getY, > boost::ref(f))) (); > ==================== [Nat] This might work better if you were to use boost::lambda::bind() rather than boost::bind()?

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Test of e-mail client - please ignore.
by Brian Allison 03 Feb '06

03 Feb '06

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Bind/lambda arithmetic question
by Stephen Gross 03 Feb '06

03 Feb '06

Ok, I want to create a functor that takes no arguments and returns a double. Furthermore, I want this functor to be composed of functors itself. For instance: ============================= struct Foo { double getX() const{ return 5; } double getY() const { return 10; } }; Foo f; double z = (boost::bind(&Foo::getX, boost::ref(f)) / boost::bind(&Foo::getY, boost::ref(f))) (); ==================== The above code, however, generates the following error: error: no match for 'operator/' in 'boost::bind(R (T::*)() const, A1) [with R = double, T = Foo, A1 = boost::reference_wrapper<Foo>](boost::ref(T&) [with T = Foo]()) / boost::bind(R (T::*)() const, A1) [with R = double, T = Foo, A1 = boost::reference_wrapper<Foo>](boost::ref(T&) [with T = Foo]())' Is there a way to make the division operation of two functors work in this example? Thanks, --Steve Stephen Gross Case Western School of Medicine Cleveland, OH "By Grabthar's hammer, by the sons of Worvan, you shall be avenged." - Dr. Lazarus

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Re: [Boost-users] Binding to a static member function?
by raulh39＠ya.com 03 Feb '06

03 Feb '06

Stephen Gross wrote: >I'm trying to figure out the correct syntax for boost::bind-ing a static >member function with some arguments preset. ... > > This code works for me: #include <boost/bind.hpp> #include <boost/function.hpp> #include <iostream> struct Foo { static double go(int x, int y) { return x + y; } }; int main() { typedef boost::function<double(int)> functortype; functortype f = boost::bind(&Foo::go, _1, 4); std::cout << f(3) << std::endl; } Hope it helps.

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Binding to a static member function?
by Stephen Gross 03 Feb '06

03 Feb '06

I'm trying to figure out the correct syntax for boost::bind-ing a static member function with some arguments preset. For example: ============================ struct Foo { static double go(int x, int y) { return x + y; } } typedef ... functortype; functortype f = boost::bind(&Foo::go, _1, boost::constant(3)); f(3); ============================ The actual code I have is a little different; I've simplified it as the above example. At compile time, the compiler complains that it can't find a matching call for 'f(3)'. Any ideas? I can post the complete example, obviously, if that's necessary. Is my syntax for the bind statement correct? Thanks in advance, --Steve Stephen Gross Case Western School of Medicine Cleveland, OH "By Grabthar's hammer, by the sons of Worvan, you shall be avenged." - Dr. Lazarus

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installation and test...
by Alain Cormier 03 Feb '06

03 Feb '06

Hello group, I am using VS6 on Windows2000 and soon .NET2005. So we are planning to migrate to boost 1.33.1 first with VS6 and move all our application to VS8 (including boost). So, I am in the process of writing an installation / migration procedure of boost for our "3rd party manager". In summary, I want to do : 1- build boost with the right toolset 2- build regression tool 3- run regression tests of boost 4- validate regression result with boost specification from http://engineering.meta-comm.com/boost.aspx 5- integrate the newly compiled boost in our application 6- correct compilation error if any change where made in the public interface 7- run our application regression test 8- submit to our version control system I am having hard time to do all this :) So : 1- I want to know your opinion about this. Does it seems like a good practice? 2- I am unable to build the regression tools with VS6. Is It normal? Am I missing something? 3- I am unable to find a boost 1.33.1 regression test. Only Head, 1.33.0 or before? 4- Does the result on my PC should be the same then the one posted on boost site? It seems like it might be different. By analysing http://engineering.meta-comm.com/boost-regression/1_33_0/developer/summary.… discovered that for the same toolset we can have different results (goncalo-vc8 and RudbekAssociates have different results for vc-8_0 toolset) It is normal? Thank you for any feedback, help or comments. <http://engineering.meta-comm.com/boost-regression/1_33_0/RudbekAssociates.h…> Alain

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<smart_ptr> scoped_ptr with a Deleter
by Guy Peleg 03 Feb '06

03 Feb '06

Hi, How come scoped_ptr can't work with a special 'deleter' as shared_ptr? Thanks Guy __________________________________________________ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com

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Decompression Problem
by Robert Vinluan 03 Feb '06

03 Feb '06

Hi All, I'm trying to decompress only a fragment of an input stream. I tried using boost::iostreams::copy() by passing in a value for the buffer_size parameter. Here's a code example of what I was trying to do: filtering_stream<input> in; in.push(gzip_decompressor()); // 'istr' is an istrstream holding the compressed data. in.push(istr); // I was hoping this would copy only the first 4 decompressed bytes!! boost::iostreams::copy(in, cout, 4); However, when I execute this, the copy() algorithm copies all decompressed data, ignoring my 'value' of 4. Perhaps I've misread the documentation? Anyway, I'm not sure if this is the correct approach to solve the problem, or even if there is a solution using boost. Any suggestions would be helpful. Thanks in advance, Rob P.S. I'm a newbie, so please let me know if this isn't the correct place to post this message.

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