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regular expression for random word wrap to multiple line
by Winson Yung 28 Jul '06

28 Jul '06

Hi all, I am not sure this is an old topic or not, but I cannot seem to find an answer for this. I have a table, because of the table column width restriction, some of the line in a table row/field gets wrapped around to second/third lines. Here is a simple illustrated the issue: sales and marketing (excludes stock-based compensation of $817, $369 and $113 for 2005, 2004 AND 2003, RESPECTIVELY) 74,823 36,000 21,162 As you can see the description txt gets break down into three lines. If I write something like this "^sales and marketing (excludes stock-based compensation of", it's not gonna capture the entire line that ended with numbers. The exact location where the line gets wrapped around is not known, so it's impossible to craft the regular expression like this beforehand. Is there a way to write *ONE* regular expression to handle this? /Winson.

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Re: [Boost-users] default copy constructors
by Andrew McDonald 28 Jul '06

28 Jul '06

> I have a specific c++ question, and was wondering whether someone > could offer some advice. It is probably better to post such questions to comp.lang.c++ or comp.lang.c++.moderated > ie is it safe to assume that Test's copy constructor will call the > copy constructor of all the above attributes. >From the C++ standard ISO/IEC 14882:1998(E) Section 12.8.8; The implicitly defined copy constructor for class X performs a memberwise copy of its subobjects. The order of copying is the same as the order of initialization of bases and members in a user defined constructor (see 12.6.2). Each subobject is copied in the manner appropriate to its type: - if the subobject is of class type, the copy constructor for the class is used; - if the subobject is an array, each element is copied, in the manner appropriate to the element type; - if the subobject is of scalar type, the builtin assignment operator is used. Virtual base class subobjects shall be copied only once by the implicitly defined copy constructor (see 12.6.2). regards, Andrew McDonald System Architect Norwood Systems Australia Pty Ltd Level 1, 71 Troy Terrace PO Box 1281 Subiaco, WA 6904 Tel +61 8 9380 7766 Fax +61 8 9380 7733 The information in this email, and any attachments, may contain confidential information and is intended solely for the attention and use of the named addressee (s). It must not be disclosed to any person(s) without authorization. If you are not the intended recipient, or a person responsible for delivering it to the intended recipient, you are not authorized to, and must not, disclose, copy, distribute, or retain this message or any part of it. If you have received this communication in error, please notify the sender immediately.

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regular expression help
by llwaeva＠21cn.com 28 Jul '06

28 Jul '06

Hi there, I am going to retrieve the following pattern %K{xxx} where xxx can be anything except line break. I find and modify the following code from document, is that right for my case? boost::regex expK("[^%]*%K{([^\r\n])}"); std::string::const_iterator start, end; start = sourcesrc.begin(); end = sourcesrc.end(); boost::match_results<std::string::const_iterator> what; boost::match_flag_type flags = boost::match_default; while ( regex_search(start, end, what, expK, flags) ) { // handle the match string, i.e. xxx my_fun( std::string( what[1].first, what[1].second ) ); start = what[1].second; flags |= boost::match_prev_avail; flags |= boost::match_not_bob; } Here, expK found all the substring matching %K{xxx} (not including double % case). But the program didn't give me what I want, I guess the problem is from the expression where { and } is not expressed correctly. However, I didn't found how to express { and } in the document. Here is my guess of the correct form, tell me if it is correct or not 1) boost::regex expK("[^%]*%K\{([^\r\n])\}"); // here \{ represents { and \} represents } 2) boost::regex expK("[^%]*%K[{]{1}([^\r\n])[}]{1}"); // use [{]{1} and [}]{1} to limit the { and } occur once exactly 3) boost::regex expK("[^%]*%K\\{([^\r\n])\\}"); // here \\{ represents { and \\} represents } which one is correct? or all is wrong? Please help! Thanks in advance.

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error in regex_replace!?
by llwaeva＠21cn.com 28 Jul '06

28 Jul '06

Hi there, I am using regex_replace to find_replace a pattern. The code is shown below string src = "xxx%R__xy\r\n%\r\nRyyyy% A__%%A\r\n%Rzzz%C%Appp_%C0123\r\n%Rooo"; re = "(%R)|(%A)|(%C)"; format = "(?1#R)(?2#A)(?3#C)"; cout << "SOURCE:" << endl << src << endl << endl; regex_replace( src.begin(), src.begin(), src.end(), re, format, format_all ); cout << "OUTPUT:" << endl << src << endl << endl; 1) For replacing %R with #R, %A with #A and %C with #C, and the output string save back to the source string, the above code do a good job. And the output is xxx#R__xy % Ryyyy% A__%#A #Rzzz#C#Appp_#C0123 #Rooo NOTE that %%A is replaced with %#A 2) If I change the format so that the length of format longer than that of subsitute string, e.g. re = "(%R)|(%A)|(%C)"; format = "(?1#RRR)(?2#AAA)(?3#CCC)"; regex_replace raise an error. I think the error is come from the original string is not long enough to store the output string. The problem can be solved by the following code string src = "xxx%R__xy\r\n%\r\nRyyyy% A__%%A\r\n%Rzzz%C%Appp_%C0123\r\n%Rooo"; string output=src; re = "(%R)|(%A)|(%C)"; format = "(?1#RRR)(?2#AAA)(?3#CCC)"; cout << "SOURCE:" << endl << src << endl << endl; regex_replace( output.begin(), src.begin(), src.end(), re, format, format_all); cout << "OUTPUT:" << endl << output << endl << endl; But I do want the output store in the original string. Reassigning the source string slove the problem, i.e. src = output, but for a large input string (for my case , >5M), this way is not that good. I am looking for a better approach. BTW, if the length of the output string shorter than the original string, the output carry some other extra characerts. e.g. string src = "xxx%Ry%Az%Ce"; string output=src; re = "(%R)|(%A)|(%C)"; format = "(?1R)(?2A)(?3C)"; The output is "xxxRyAzCe%Ce" where the last %Ce are extra characters from source string. How can I kill the extra characters? 3) Finally, I will modify the search condition to make sure that only %X rather than %%X (X can be R, A or C) is replaced. I try the following regular expression re = "([^%]%R)|([^%]%A)|([^%]%C)"; but it doesn't work properly for my problem. e.g. for src = "xxx%R %%R", for the format "(?1#R)(?2#A)(?3#C)"; the regular expression will kill the 'x' before %R, i..e. the output is "xx#R %%R" rather than "xxx#R %%R" Please help! Thanks in advance.

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Labeling patched Boost versions
by Daniel Krügler 28 Jul '06

28 Jul '06

Hello, Recently I had a discussion with a colleague concerning the possibility to influence the resulting file names of the default boost output. This discussion was actually inspired by the outcome of thread "[thread] Keeping leak detectors still..." on 2006-07-11 where we had the situation of an inofficial patch which we would like to use. The problem is: How can/should I signal a patched boost version? According to the naming scheme described in http://boost.org/more/getting_started.html one could change the boost subminor version. Regrettably we found out that most programmers actually expect that such a number belongs to one of the *official* boost versions provided by http://boost.org/, (most probably because the naming scheme smoothly integrates). Now I had the idea of an optional "build id", which is a well-known tool in many projects to signal a given state or "snap shot". The very advantage of a build id - which's format is usually not fixed, but typically is a string of numbers, letters and some file-name compatible characters like '-', normally without any white spaces and of arbitrary length - is, that it accentuates and differs very strongly from the regular pattern of the subdivided version number. Ideally it should be possible to define a kind of bjam constant, e.g -sBUILD_ID=string (I'm not a bjam expert and I hope that the above proposed name does not violate any naming policies of such configuration parameters), which would allow to explicitly set build id for a bjam build. I have no strong opinion concerning the exact position of that build id in a lib name, but probably the most resonable one would be just after the version number, e.g. libboost_date_time-gcc-mt-d-1_31_M20060721.a for -sBUILD_ID=M20060721 Does there already exist such a possibility to do that and if not: I would really appreciate such a general available "callback" for injecting a build id (a sequence of characters) into the final output. Standard behaviour would of course be, *not* to attach such id, but the possibility to do that via a userdefined program parameter of bjam would be fantastic! The problem is: If I would manually hack the boost bjam files to do just this, I could never update to the next boost version without fears, because I always would need to manipulate the new version also. Since I assume that this request is of general interest for the community I would like to humbly ask for support of it. What do you think? Any chances for that idea? Or better ones? Greetings from Bremen, Daniel Krügler

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DateTime: Seconds until next month
by Olaf van der Spek 28 Jul '06

28 Jul '06

Hi, I'm currently using the following code to calculate the number of seconds until the next month. I'm wondering whether there's an easier way. date d(day_clock::universal_day()); d += months(1); cout << duration2a((ptime(date(d.year(), d.month(), 1)) - second_clock::universal_time()).total_seconds()) + " until ladders reset" << endl; return 0;

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regex_replace help
by llwaeva＠21cn.com 28 Jul '06

28 Jul '06

Hi there, I am using regex_replace for string replacing. I am working with a very large string (about 3M) and need to do the following replacment %R% --> #R# %A% --> #R1# %C% --> #R2# and so on. I am new to regular express and regex. After having read the document, I know how regex works, but still not sure if regex_replace meet my demand 1) I invoke regex_replace several times to replace difference patterns. For a large input string, the operation is very slow. Can I call regex_replace once to do the several replacments. i.e. calling regex_replace( output, begin, end, "%R ,%A ,%C", "#R#, #R1#, #R2#", match_default); for replacing %R% with #R# %A% with #R1# %C% with #R2# 2) According to the document, the output fashion depends on the match_flag_type, for my case, I hope the output string, including both matched and nonmatched part, replace the whole input string. e.g. SourceStr = "xxxx%R%yyy%A%zzz%C%" Apply regex_replace( output_string, SourceStr.begin, SourceStr.end, ... ) We have , output_string = "xxxx#R#yyy#R1#zzz#R2#" rather than #R#, #R1# and #R2# Any reply will be highly appreciated.

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default copy constructors
by bringiton bringiton 28 Jul '06

28 Jul '06

I have a specific c++ question, and was wondering whether someone could offer some advice. Is is safe to assume that modern compilers will supply a default copy constructor and default assignment operator that will copy all attributes? Or may I run into undefined behaviour between compilers. class Test: public: int v1; char v2; float v3 std::string v4; std::vector<int> v5; boost::shared_ptr<int> v6; }; ie is it safe to assume that Test's copy constructor will call the copy constructor of all the above attributes. NOTE: i am only talking about attributes that are already copiable. i understand that if a class manages it's own memory, the copy constructor will need to be defined. **Just so we are using the same terminology, does c++ have a pattern to define concrete objects that are copiable? ie your basic types, int, char, float. and classes that have been designed to be copiable: ie std::string, std::vector etc. **Maybe it's called concrete type.

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Re: [Boost-users] [license] Why is the Boost license not anofficial Open Source license?
by Sohail Somani 27 Jul '06

27 Jul '06

> -----Original Message----- > From: boost-users-bounces(a)lists.boost.org > [mailto:boost-users-bounces@lists.boost.org] On Behalf Of > Gennaro Prota > Sent: Thursday, July 27, 2006 10:05 AM > To: boost-users(a)lists.boost.org > Subject: Re: [Boost-users] [license] Why is the Boost license > not anofficial Open Source license? > > With a terminology stress which (to me) twists the meaning of "free > software" it could be classified as "non-copylefted free software" > (which basically means, anyone can redistribute it under a non free > license; in the case of boost they can do that only if they don't > redistribute the source code) So if you use boost in your interfaces, you've gotta redistribute your source code too?

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Re: [Boost-users] [license] Why is the Boost license not anofficial Open Source license?
by Sohail Somani 27 Jul '06

27 Jul '06

> -----Original Message----- > From: boost-users-bounces(a)lists.boost.org > [mailto:boost-users-bounces@lists.boost.org] On Behalf Of > Sebastian Redl > Sohail Somani wrote: > > >So if you use boost in your interfaces, you've gotta > redistribute your > >source code too? > > > > > No. All he said is that you may not distribute the Boost > sources under > any license but the Boost license. It doesn't affect your own > stuff at all. Gotcha.

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